Question

What volume of water would be added to 16.5 mL of a 0.0813 M solution of sodium borate in order to get a 0.0200 M solution?

Answer 1

To solve this we'll need to apply the equation

`M_1V_1 = M_2V_2`

`V_1 = 16.5ml`
`V_2 = ?`
`M_1 = 0.0813`
`M_2 = 0.200`

Solve the equation for V2
`V_2` = `(M_1V_1)/M_2`

`V_2` = `(0.0813M . 16.5ml) / (0.0200M` = `67.1ml`

Please note the question asks you to find the volume that must be added. You'll need to subtract 16.5mL from 67.1 to find the answer of
50.6mL.

Here is a video which discusses how to perform dilution calculations.