What volume will 2.0 moles of nitrogen occupy at 720 torr and 20°C?

1 Answer
anor277
Apr 20, 2016

Approx. 50 L.

Explanation:

V=(nRT)/P = (2.0*molxx0.0821*L*atm*K^-1*mol^-1xx293*K)/((720*"mm Hg")/(760*"mm Hg"*atm^-1))

The answer is consistent with the known molar volume under standard laboratory condiitions: 25.4*L at 1*atm and 298*K.

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