Question

What weight (in grams) of `KCl` is there in 2.50 liters of 0.50M `KCl` solution?

Answer 1

`"Mass of solute"` `=` `"Concentration"xx"volume"xx"molar mass of solute"` `~=` `90*g`

Explanation:

`"Moles of solute"` `=` `2.50*Lxx0.50*mol*L^-1` `=` `1.25*mol`.

`"Mass of solute"` `=` `1.25*molxx74.55*g*mol^-1` `=` `??g`