What will be the additive inverse of #(sqrt2, sqrt3)#? Algebra Properties of Real Numbers Additive Inverses and Absolute Values 1 Answer Ratnaker Mehta Jun 6, 2017 It is #(-sqrt2,-sqrt3).# Answer link Related questions What are absolute values? What is the absolute value of -10 and 10? How do you know that the additive inverse of -20 is 20? How do you evaluate #|2-8|#? How do you simplify #-|-1|#? What is the additive inverse property? What is the absolute value of -9? How do you simplify #x = - abs6^2 - abs(-4 + 7) *7#? How do you simplify #abs( -11 +1)#? How do you simplify #abs6-abs(-3)#? See all questions in Additive Inverses and Absolute Values Impact of this question 3354 views around the world You can reuse this answer Creative Commons License