What will be the escape velocity from a planet whose mass is 6 times that of the earth and radius is twice that of the earth considering v is the eascape velocity from earth?

1 Answer
Jan 11, 2018

The escape velocity is =(sqrt3v)ms^-1

Explanation:

The escape from the earth is

v=sqrt((2GM)/r)

G is the gravitational constant

M is the mass of the earth

r= is the distance from the center of mass of the body to the object

On the planet

M_1=6M

r_1=2r

Therefore,

v_p=sqrt((2GM_1)/r_1)=sqrt((2G*6M)/(2r))

=sqrt(((2GM)/r)*3)

=sqrt3v