What will be the volume of 3.65 g of oxygen gas be at STP?

1 Answer
Jun 20, 2018

Well...V=(nRT)/PV=nRTP..I get approx. 3*L3L

Explanation:

And so P=(100*kPa)/(101.3*kPa*atm^-1)P=100kPa101.3kPaatm1...I use atmospheres instead of kPakPa because I think the units are more accessible...

V=((3.65*g)/(32.00*g*mol^-1)xx0.0821*(L*atm)/(K*mol)xx273.15*K)/((100*kPa)/(101.3*kPa*atm^-1))V=3.65g32.00gmol1×0.0821LatmKmol×273.15K100kPa101.3kPaatm1

=??*L=??L

Note that you must simply KNOW that oxygen is diatomic...in fact all the elemental gases with any chemistry are diatomic...