Question

What will be the volume of 3.65 g of oxygen gas be at STP?

Answer 1

Well...`V=(nRT)/P`..I get approx. `3*L`

Explanation:

And so `P=(100*kPa)/(101.3*kPa*atm^-1)`...I use atmospheres instead of `kPa` because I think the units are more accessible...

`V=((3.65*g)/(32.00*g*mol^-1)xx0.0821*(L*atm)/(K*mol)xx273.15*K)/((100*kPa)/(101.3*kPa*atm^-1))`

`=??*L`

Note that you must simply KNOW that oxygen is diatomic...in fact all the elemental gases with any chemistry are diatomic...