Whats the partial derivative of #f(x,y) = 2x+3e^y#?

2 Answers
Feb 26, 2018

There are two:

#(del(f(x,y)))/(delx) = 2#

#(del(f(x,y)))/(dely) = 3e^y#

Explanation:

There are two partial derivatives, one with respect to x and the other with respect to y.

To compute the partial derivative with respect to x, you treat any term that does not contain a function of x as if it were a constant that becomes 0, when the derivative is compute and you treat all other factors in terms that contain x as if they were constants.

#(del(f(x,y)))/(delx) = (del(2x+3e^y))/(delx)#

You treat #3e^y# as a constant that will become 0 and the derivative of #2x# with respect to x is just 2:

#(del(f(x,y)))/(delx) = 2#

You do the same thing when you compute the partial derivative with respect to y.

#(del(f(x,y)))/(delx) = (del(2x+3e^y))/(delx)#

You treat the #2x# as if it were a constant and the derivative of #3e^y# with respect to y is #3e^y#:

#(del(f(x,y)))/(delx) = 3e^y#

Feb 26, 2018

#(delf)/(delx)=2#,#(delf)/(dely)=3e^y#

Explanation:

#f(x,y)=2x+3e^y#
While finding partial derivative w.r.t.#x#, the change in #f(x,y)# is due to change in the variable #x# alone whereas #y# remains constant.
So, #(delf)/(delx)=2(1)=2#
similarly, while finding partial derivative w.r.t.#y#, the change in #f(x,y)# is due to change in the variable #y# alone whereas #x# remains constant.
Hence, #(delf)/(dely)=3e^y#