Whats the slope of a line perpendicular to $x - y = 16$ $x - y = 16$ ?

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Whats the slope of a line perpendicular to $x - y = 16$ $x - y = 16$ ?

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Answer 1 · 2015-07-22T15:02:42

All lines perpendicular to $x - y = 16$ $x-y = 16$
have a slope of $- 1$ $-1$

Explanation:

$x - y = 16$ $x - y = 16$ has a slope of $1$ $1$
$XXXX$ $color(white)("XXXX")$ (this can be demonstrated by:
$XXXX$ $color(white)("XXXX")$ $XXXX$ $color(white)("XXXX")$ $\circ$ $@$ converting to slope-point form
$XXXX$ $color(white)("XXXX")$ $XXXX$ $color(white)("XXXX")$ or
$XXXX$ $color(white)("XXXX")$ $XXXX$ $color(white)("XXXX")$ $\circ$ $@$ using the slope $= - \frac{b}{a}$ $= -b/a$ formula)

If a line has a slope of $m$ $m$
$XXXX$ $color(white)("XXXX")$ all lines perpendicular to it have a slope of $(- \frac{1}{m})$ $(-1/m)$

Therefore all lines perpendicular to $x - y = 16$ $x-y = 16$
$XXXX$ $color(white)("XXXX")$ have a slope of $(- 1)$ $(-1)$

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Whats the slope of a line perpendicular to $x - y = 16$ $x - y = 16$ ?

1 Answer

Explanation:

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Whats the slope of a line perpendicular to x−y=16x - y = 16?

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Whats the slope of a line perpendicular to $x - y = 16$ $x - y = 16$ ?