When the following equation is balanced in standard form, what is the coefficient in front of CO2(g)? C2H6(g) + O2(g) ® CO2(g) + H2O(l) A)1 B)2 C)3 D)4 E)5

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When the following equation is balanced in standard form, what is the coefficient in front of CO2(g)? C2H6(g) + O2(g) ® CO2(g) + H2O(l) A)1 B)2 C)3 D)4 E)5

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Answer 1 · 2015-02-24T01:37:32

The balanced equation is:

$C_{2} H_{6 (g)} + 3 \frac{1}{2} O_{2 (g)} \to 2 C O_{2 (g)} + 3 H_{2} O_{(l)}$ $C_2H_(6(g))+3(1)/(2)O_(2(g))rarr2CO_(2(g))+3H_2O_((l))$

In this case the coefficient is 2.

I could double everything then it would be 4.

I guess that is what you mean by "standard form"?

Answer 2 · 2015-02-24T01:42:36

The balanced chemical equation for the combustion of ethane, or $C_{2} H_{6}$ $C_2H_6$ , looks like this

$2 C_{2} H_{6 (g)} + 7 O_{2 (g)} \to 4 C O_{2 (g)} + 6 H_{2} O_{(l)}$ $2C_2H_(6(g)) + 7O_(2(g)) -> 4CO_(2(g)) + 6H_2O_((l))$

This means that the coefficient in front of $C O_{2}$ $CO_2$ will be 4 - option D.

SIDE NOTE You'll sometimes see this written with fractional coefficients, but the standard form equation has coefficients that are integers for all species involved.

$C_{2} H_{6} + 3.5 O_{2} \to 2 C O_{2} + 3 H_{2} O$ $C_2H_6 + 3.5O_2 -> 2CO_2 + 3H_2O$ $\to$ $->$ don't use this version when asked for standard form.

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When the following equation is balanced in standard form, what is the coefficient in front of CO2(g)? C2H6(g) + O2(g) ® CO2(g) + H2O(l) A)1 B)2 C)3 D)4 E)5

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