When the formula equation Fe_3O_4 + Al -> Al_2O_3 + FeFe3O4+AlAl2O3+Fe is correctly balanced what is the coefficient of FeFe?

1 Answer
May 27, 2018

Well...Fe_3O_4Fe3O4 is a mixed valence oxide...Fe_3O_4-=FeO*Fe_2O_3Fe3O4FeOFe2O3

3Fe_3O_4 +8Al rarr9Fe +4Al_2O_33Fe3O4+8Al9Fe+4Al2O3

Explanation:

And so the oxides are reduced to iron...

FeO+2H^+ +2e^(-)rarrFe + H_2OFeO+2H++2eFe+H2O (i)(i)

Fe_2O_3 +6H^+ +6e^(-)rarr2Fe+3H_2OFe2O3+6H++6e2Fe+3H2O (ii)(ii)

And aluminim metal is oxidized to alumina...

2Al +3H_2OrarrAl_2O_3+6H^+ +6e^-2Al+3H2OAl2O3+6H++6e (iii)(iii)

And we add 3xx(i)+3xx(ii)+4xx(iii)3×(i)+3×(ii)+4×(iii)

3Fe_2O_3 +24H^+ +18e^(-)+3FeO+6H^+ +6e^(-)+8Al +12H_2Orarr3Fe + 3H_2O+6Fe+9H_2O+4Al_2O_3+24H^+ +24e^-3Fe2O3+24H++18e+3FeO+6H++6e+8Al+12H2O3Fe+3H2O+6Fe+9H2O+4Al2O3+24H++24e

And now we cancel common reagents...

underbrace(3Fe_2O_3 +3FeO)_(3Fe_3O_4) +8Al rarr6Fe +4Al_2O_3+Delta

And finally....

3Fe_3O_4 +8Al rarr9Fe +4Al_2O_3

And this looks balanced to me... but please check my 'rithmetic; all care taken but no responsibility admitted. And this is an important reaction practically. Where there is a join in the track of a railway line, they fill it with the iron oxide and alumina, and have at it with a blow torch. The aluminum oxidizes to alumina (and is expelled from the join), and the molten iron welds the track together....