When working in decimal radians, how do you find x given $65^{0}$ $65^0$ = ${sin}^{- 1} x$ $sin^-1 x$ ? ?

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Answer 1 · 2015-08-14T12:30:47

x = ${sin 65}^{0}$ $sin 65^0$ = sin $65 \cdot \frac{π}{180}$ $65* pi/180$ = sin $13 \frac{π}{36}$ $13pi/36$

$π$ $pi$ rad = $180^{0}$ $180^0$
Also $θ$ $theta$ = ${sin}^{- 1}$ $sin^-1$ x $\Rightarrow$ $=>$ x = sin $θ$ $theta$

When working in decimal radians, how do you find x given 65065^0 = sin−1xsin^-1 x ? ?