Since cot(theta)=1/tan(theta)cot(θ)=1tan(θ), it follows that cot^{-1}(5)cot−1(5) can be thought of as an angle thetaθ in a right triangle where the ratio of the adjacent side over the opposite side is 5=5/15=51. Therefore, the tangent of that angle thetaθ is 1/515 (opposite over adjacent).
Now the tangent function is an odd function, so tan(-theta)=-1/5tan(−θ)=−15 and therefore tan^{-1}(-1/5)=-thetatan−1(−15)=−θ. It follows that tan^{-1}(-1/5)tan−1(−15) is the answer you want. Now use your calculator (in radian mode).