Which coefficients correctly balance the formula equation $N H_{4} N O_{2} (s) \to N_{2} O (g) + H_{2} O (l)$ $NH_4NO_2(s) -> N_2O(g) + H_2O(l)$ ?

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Answer 1 · 2017-05-19T16:29:29

$2 N H_{4}^{+} + 4 N O_{2}^{-} + 2 H^{+} \to 3 N_{2} O + 5 H_{2} O$ $2NH_4^(+) +4NO_2^(-) +2H^(+)rarr 3N_2O +5H_2O$

This is a so-called $comproportionation reaction .$ $"comproportionation reaction".$

$Oxidation half equation:$ $"Oxidation half equation:"$

$2 N H_{4}^{+} + H_{2} O \to N_{2} O + 10 H^{+} + 8 e^{-}$ $2NH_4^(+) +H_2O rarr N_2O+10H^(+) + 8e^(-)$ $(i)$ $(i)$

Ammonium ion is oxidized to $N_{2} O$ $N_2O$

$Reduction half equation:$ $"Reduction half equation:"$

$2 N O_{2}^{-} + 6 H^{+} + 4 e^{-} \to N_{2} O + 3 H_{2} O$ $2NO_2^(-) +6H^+ +4e^(-) rarr N_2O+3H_2O$ $(i i)$ $(ii)$

Nitrite ion is reduced to $N_{2} O$ $N_2O$

And we take $(i) + 2 \times (i i)$ $(i) + 2xx(ii)$ to eliminate the electrons........

$2 N H_{4}^{+} + 4 N O_{2}^{-} + 2 H^{+} \to 3 N_{2} O + 5 H_{2} O (l)$ $2NH_4^(+) +4NO_2^(-) +2H^(+)rarr 3N_2O +5H_2O(l)$

Which coefficients correctly balance the formula equation NH_4NO_2(s) -> N_2O(g) + H_2O(l)NH4NO2(s)→N2O(g)+H2O(l)NH_4NO_2(s) -> N_2O(g) + H_2O(l)?