Which compounds are the Bronsted-Lowry bases in this equilibrium: $H C_{2} O_{4}^{- +} H_{2} B O_{3}^{-} ⇌ H_{3} B O_{3} + C_{2} O_{4}^{2 -}$ $HC_2O_4^- + H_2BO_3^(-) rightleftharpoons H_3BO_3 + C_2O_4^(2-)$ ?

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Which compounds are the Bronsted-Lowry bases in this equilibrium: $H C_{2} O_{4}^{- +} H_{2} B O_{3}^{-} ⇌ H_{3} B O_{3} + C_{2} O_{4}^{2 -}$ $HC_2O_4^- + H_2BO_3^(-) rightleftharpoons H_3BO_3 + C_2O_4^(2-)$ ?

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Answer 1 · 2017-04-01T11:17:21

The base is the proton acceptor............

Explanation:

And thus in the given reaction, the oxalic acid salt is the acid, which means that ${(H O)}_{2} B O^{-}$ $(HO)_2BO^(-)$ , the boric acid salt, is the base............

$underbrace(""^(-)"O(O=)CC(=O)OH")_color(red)"the acid" + underbrace("(HO)"_2"BO"^(-))_color(blue)"the base"rarr^(-)"O(O=)CC(=O)O"^(-) +"B(OH)"_3$

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Which compounds are the Bronsted-Lowry bases in this equilibrium: $H C_{2} O_{4}^{- +} H_{2} B O_{3}^{-} ⇌ H_{3} B O_{3} + C_{2} O_{4}^{2 -}$ $HC_2O_4^- + H_2BO_3^(-) rightleftharpoons H_3BO_3 + C_2O_4^(2-)$ ?

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Explanation:

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Which compounds are the Bronsted-Lowry bases in this equilibrium: HC_2O_4^- + H_2BO_3^(-) rightleftharpoons H_3BO_3 + C_2O_4^(2-)HC2O−+4H2BO−3⇌H3BO3+C2O2−4HC_2O_4^- + H_2BO_3^(-) rightleftharpoons H_3BO_3 + C_2O_4^(2-)?

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Explanation:

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Which compounds are the Bronsted-Lowry bases in this equilibrium: $H C_{2} O_{4}^{- +} H_{2} B O_{3}^{-} ⇌ H_{3} B O_{3} + C_{2} O_{4}^{2 -}$ $HC_2O_4^- + H_2BO_3^(-) rightleftharpoons H_3BO_3 + C_2O_4^(2-)$ ?