What is the balanced equation for $S_{8} + O_{2} \to S O_{2}$ $S_8+O_2->SO_2$ ?

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Answer 1 · 2016-04-14T22:14:02

$S_{8} (s) + 8 O_{2} (g) \to 8 S O_{2} (g)$ $S_8(s) + 8O_2(g) rarr 8SO_2(g)$

Alternatively I could use a non-integral stoichiometric coefficient for sulfur:

$\frac{1}{8} S_{8} (s) + O_{2} (g) \to S O_{2} (g)$ $1/8S_8(s) + O_2(g) rarr SO_2(g)$ , or more simply,

$S (s) + O_{2} (g) \to S O_{2} (g)$ $S(s) + O_2(g) rarr SO_2(g)$

This form might make the arithmetic a bit easier. What is the oxidation state of $S$ $S$ in $S O_{2}$ $SO_2$ ?

What is the balanced equation for S8+O2→SO2S_8+O_2->SO_2?