Which ordered pair is the solution to the system of equations #y=x# and #y=x^2-2#?
1 Answer
Aug 24, 2016
Explanation:
If the first equation is satisfied then we can replace
#x = x^2-2#
Subtract
#0 = x^2-x-2 = (x-2)(x+1)#
Hence solutions
To make each of these into ordered pair soltuions of the original system, use the first equation again to note that
So the ordered pair solutions to the original system are:
#(2, 2) " "# and#" " (-1, -1)#