Which quadrant does the given angle 621 degrees lie?

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Answer 1 · 2016-11-11T04:41:00

$Q_3$

If I remember correctly, this was my way of finding the Q of any

$theta^o$ :

Let q = int ( $theta/90$ ) be the quotient from the division

$theta/90$ .

If q is even and a multiple of 4, $theta in Q_1$ ;

otherwise $theta in Q_3$ .

If q is odd and the remainder in ( q/4 ) is 1, $theta in Q_2$ ;

otherwise $theta in Q_4$ .

Here, int ( 621/90 ) = 6 that is even but not a multiple of 4.

So, $621^o in Q_3$ .

For that matter, int ( 711/90 )= 7 that is odd but not a multiple of 3. So,

$711^o in Q_4$ ,

Int ( 801/80 )= 8 that is even but a multiple of 4. So, $801^o in Q_1$

Int (891/80)= 9 that is odd but a multiple of 3. So, $891^o in Q_2$

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