Which would contain 9.03 × 10^23 oxygen atoms? A) 0.25 mol aluminium oxide B) 0.75 mol sulfur dioxide C) 1.5 mol sulfur trioxide D) 3.0 mol water

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Which would contain 9.03 × 10^23 oxygen atoms? A) 0.25 mol aluminium oxide B) 0.75 mol sulfur dioxide C) 1.5 mol sulfur trioxide D) 3.0 mol water

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Answer 1 · 2017-11-25T15:47:23

Well one mole of stuff specifies $6.022 \times 10^{23}$ $6.022xx10^23$ individual items of stuff.....

Explanation:

But of course we must specify the item. In the first scenario we gots $0.25 \cdot m o l$ $0.25*mol$ $aluminium oxide$ $"aluminium oxide"$ , i.e. $A l_{2} O_{3}$ $Al_2O_3$ ..approx. $4.5 \times 10^{23} \cdot oxygen atoms$ $4.5xx10^23*"oxygen atoms"$ ...

And in the second scenario we gots $6.022 \times 10^{23} \cdot m o l^{- 1} \times 2 \times 0.75 \cdot m o l$ $6.022xx10^23*mol^-1xx2xx0.75*mol$ $oxygen atoms = 9.0 \times 10^{23} \cdot oxygen atoms$ $"oxygen atoms"=9.0xx10^23*"oxygen atoms"$ . So it looks like scenario 2 is the winner. And scenario 3 and 4 contain too many oxygen atoms to fulfil your given criterion.

Answer 2 · 2017-11-25T15:52:55

$B$ $B$

Explanation:

$0.75$ $0.75$ mol sulphur dioxide = $0.75$ $0.75$ mol of sulphur $+ 1.5$ $+1.5$ mol of oxide

$1.5$ $1.5$ mol = $1.5 \cdot 6.02 \cdot 10^{23} = 9.03 \cdot 10^{23}$ $1.5 * 6.02 * 10^23 = 9.03*10^23$

$1.5$ $1.5$ mol of oxide = $0.75$ $0.75$ mol dioxide = $9.03 \cdot 10^{23}$ $9.03*10^23$ oxygen atoms

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Which would contain 9.03 × 10^23 oxygen atoms? A) 0.25 mol aluminium oxide B) 0.75 mol sulfur dioxide C) 1.5 mol sulfur trioxide D) 3.0 mol water

2 Answers

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