Alkenes, olefins, have the "ONE DEGREE OF UNSATURATION...."
...............A very useful idea that is used to rationalize the formulae of organic compounds is the "degree of unsaturation". An alkane is fully "saturated", and it contains the MAXIMUM ALLOWABLE number of C-H bonds.
From a prior answer on this topic....
Alkanes are "FULLY saturated" and have a general formula of C_nH_(2n+2). Try this out for "methane," "ethane," ........."pentane, etc." The number of oxygen atoms present in the formula does not affect this calculation.
Each double bond, each olefinic bond or carbonyl group, OR a ring junction, corresponds to 1""^@ of unsaturation; i.e. 2 hydrogens LESS than the saturated formula. So according to the scheme, "ethane" has the saturated formula of H_3C-CH_3, but "ethylene", H_2C=CH_2, and "acetaldehyde", H_3C-C(=O)H has 1^@ of unsaturation. Halogen atoms count for one hydrogen; for nitrogen atoms, substract NH from the formula before assessing unsaturation; i.e. for "ethylamine," H_2NCH_2CH_3 rarr C_2H_6, i.e. "no degrees of unsaturation".
