For first-row transition metals, why do the 4s orbitals fill up before the 3d orbitals? And why are electrons lost from 4s orbitals before 3d orbitals?

1 Answer
Apr 15, 2018

For scandium through zinc, the #4s# orbitals fill AFTER the #3d# orbitals, AND the #4s# electrons are lost before the #3d# electrons (last in, first out). See here for an explanation that does not depend on "half-filled subshells" for stability.


See how the #3d# orbitals are lower in energy than the #4s# for the first-row transition metals here (Appendix B.9):

Data from Appendix B.9 of Inorganic Chemistry by Miessler, Fischer, and Tarr

All the Aufbau Principle predicts is that electron orbitals are filled from lower energy to higher energy... whatever order that may entail.

The #4s# orbitals are higher in energy for these transition metals, so naturally they tend to fill LAST (especially for late transition metals, where #V_(3d) "<<" V_(4s)#), not first.

Hence, it makes sense that the #4s# electron is predicted to be ionized first (barring #3d-4s# interactions), at least for the first ionization.