Will these reactions yield an acidic, basic or neutral solution?

Question

2142 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-09T22:49:14

We assume one equiv EACH of the given reagents.........

And thus for $a.,b.,c.$ we gets acidic, slightly basic, and basic solutions.

And we should write the stoichiometric equations:

$a.$ $H_2SO_4(aq) +NH_3(aq) rarr NH_4^+ + HSO_4^-$

The solution is ACIDIC because of the acidity of both bisulfate and ammonium ions:

$HSO_4^(-) +H_2O rightleftharpoons H_3O^+ + SO_4^(2-)$

$b.$ $HCO_2H(aq) +KOH(aq) rarr HCO_2^(-)K^+ + H_2O(l)$

and potassium formate gives a slightly basic solution.......

$K^+HCO_2^(-) +H_2O rightleftharpoons HCO_2H(aq) + KOH(aq)$

The solution is ALKALINE because of the basicity of the formate ions.

$(c)$ $CaCO_3(s) + HNO_3(aq) rightleftharpoons [CaHCO_3]^ + +NO_3^(-) +H_2O$

The solution should be more or less neutral.