Work out? Two identical charged bodies are 3 cm apart exert a force of $4 × 10^-4\ "N"$ on each other. The charge on each body is_______? Thanks

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Answer 1 · 2018-06-07T11:25:11

$"6.32 nC"$

From Coulomb’s Law

$"F" = ("kq"_1"q"_2)/"d"^2$

It’s given that bodies are identically charged. So, $"q = q"_1 = "q"_2$

$"F" = "kq"^2/"d"^2$

From above

$"q = d"sqrt("F"/"k")$

$color(white)("q") = "0.03 m" × sqrt((4 × 10^-4\ "N")/(9 × 10^9\ "N m"^2"/C"^2))$

$color(white)("q") = 6.32 × 10^-9\ "C"$

$color(white)("q") = 6.32\ "nC"$

Work out? Two identical charged bodies are 3 cm apart exert a force of 4 × 10^-4\ "N"4 × 10^-4\ "N" on each other. The charge on each body is_______? Thanks