Question

Would`f(x)=root(3)( -x+2)` be a odd function?

Answer 1

No; it is neither odd nor even.

Explanation:

The test for odd is `f(-x) = -f(x)`:

`f(-x) = root(3)(-(-x) + 2) = root(3)(x + 2)`

`-f(x) = -root(3)(-x + 2) = root(3)((-1)^3(-x + 2)) = root(3)(x - 2)`

`root(3)(x - 2) !=root(3)(x + 2)`

Not odd

The test for even is `f(x) = f(-x)`

`root(3)(-x + 2) != root(3)(x + 2)`

Not even.

`:.` Neither