Write the complex number $(8 - i) - (3+2i) + (-4 + 6i)$ in standard form?

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Answer 1 · 2015-05-13T22:12:42

Start by getting rid of the brackets (considering the signs in front of them):

$8-i-3-2i-4+6i=$

Now add together Real parts and Immaginary parts:

$=1+3i$

which is in the form $a+ib$

Write the complex number (8 - i) - (3+2i) + (-4 + 6i)(8 - i) - (3+2i) + (-4 + 6i) in standard form?