x+y+z=1,3x+y+4z=8,xy+7z=9?

2 Answers
Nov 9, 2017

x=3
y=5
z=1

Explanation:

There are three equations with three variables.

Make y the subject in all three equations:

y=xz1 ..... equation 1
y=3x4z+8 ... equation 2
y=x+7z9 ...equation 3

By equating the equations in pairs we can form two equations with the variables xandz and solve them simultaneously

Using equations 1 and 2: y=y

xz1=3x4z+8
3xx+4zz=8+1 re-arrange

2x+3z=9 equation A

Using equations 3 and 2 y=y

x+7z9=3x4z+8 re-arrange

3xx+7z+4z=8+9

2x+11z=17 equation B

Now solve A and B for xandz

2x+11z=17mmmmmmmmmmmA
2x+3z=9mmmmmmmmmmmmB

AB: 8z=8
mmmmmmz=1

2x+3(1)=9
2x+3=9
2x=6
x=3

Now find y from equation 1
y=xz1
y=(3)(1)1
y=5

Check with equation 2

y=3x4z+8
y=3(3)4(1)+8
y=94+8
y=5

Nov 9, 2017

x=3, y=5 and z=1

Explanation:

x+y+z=1, 3x+y+4z=8 an xy+7z=9

From first equation, z=xy1

Plug z into second an third ones;

3x+y+4(xy1)=8

3x+y4x4y4=8

x3y=12

xy+7(xy1)=9

xy7x7y7=9

8x8y=16

8(x+y)=16 or x+y=2

From second one, x=3y12

Plug x into third one;

(3y12)+y=2

2y12=2

2y=10, so y=5

Hence x=3y12=(3)(5)12=3

Thus, z=xy1=3(5)1=1