Differentiate the function. Y= √x(x-8) ?

1 Answer
Massimiliano
Mar 3, 2015

The answer is: (x-4)/sqrt(x^2-8x)x−4√x2−8x.

y=sqrt(x(x-8))rArry=sqrt(x^2-8x)rArry=√x(x−8)⇒y=√x2−8x⇒

y'=1/(2sqrt(x^2-8x))*(2x-8)=(2(x-4))/(2sqrt(x^2-8x))=(x-4)/sqrt(x^2-8x).

Related questions
See all questions in What is Calculus?
Impact of this question
5673 views around the world
You can reuse this answer
Creative Commons License