You are planting a rectangular garden. It is 5 feet longer than 3 times its width. The area of the garden is 250 ft. How do you find the dimensions of the garden?

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You are planting a rectangular garden. It is 5 feet longer than 3 times its width. The area of the garden is 250 ft. How do you find the dimensions of the garden?

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Answer 1 · 2017-01-10T04:48:59

Length = 30ft, width = 25/3 ft

Explanation:

Let say width(W) = x. Then length(L) = 3x+5

$A r e a = W \cdot L$ $Area = W*L$
$(x) (3 x + 5) = 250$ $(x)(3x+5)=250$
$3 x^{2} + 5 x = 250$ $3x^2+5x=250$
$3 x^{2} + 5 x - 250 = 0$ $3x^2+5x-250=0$
$(3 x - 25) (x + 10) = 0$ $(3x-25)(x+10)=0$

$x = \frac{25}{3} and x = - 10$ $x=25/3 and x=-10$
since it unit cannot be -ve,
$therefore x = 25/3 only$

$W=25/3ft$
$L =3(25/3)+5 = 30ft$

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You are planting a rectangular garden. It is 5 feet longer than 3 times its width. The area of the garden is 250 ft. How do you find the dimensions of the garden?

1 Answer

Explanation:

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