What is the derivative of #y=sec^3(x)#?
1 Answer
Aug 6, 2014
Thus,
And, we know that this is equivalent to
So, all we need to do is use the power rule, keeping in mind to use the chain rule on
#dy/dx = -3*(cos x)^(-4) * d/dx[cos x]#
#= -3*(cos x)^(-4) * (-sinx)#
#= 3sinx(cos x)^(-4) #
#= (3sinx)/(cos^4 x) #