Derivatives of y=sec(x), y=cot(x), y= csc(x)

Key Questions

  • d/dx sec(x)=sec(x)tan(x)ddxsec(x)=sec(x)tan(x)

    You could memorize this, but you can work it out too by knowing some trig properties.

    The trig properties we will use are:
    sec (x)= 1/cos(x)sec(x)=1cos(x)
    and sin x/cos x=tan xsinxcosx=tanx

    Deriving:
    d/dx sec (x) = d/dx 1/cos(x) = (cos (x)(0) - 1 (-sin (x)))/( cos (x)cos (x))ddxsec(x)=ddx1cos(x)=cos(x)(0)1(sin(x))cos(x)cos(x) (using the quotient rule)
    = sin (x)/ (cos (x) cos (x)) = sin(x)/cos(x) *(1/cos( x)) = tan (x) sec( x)=sec (x) tan (x)=sin(x)cos(x)cos(x)=sin(x)cos(x)(1cos(x))=tan(x)sec(x)=sec(x)tan(x)

Questions