Differentiate $\frac{sin x}{5 x + {sec}^{2} x}$ $sinx/(5x+sec^2x)$ ?

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Answer 1 · 2017-06-07T18:45:56

$y' = frac{cos x (5x + sec^2 x) - sin x (5 + 2 sec x frac{1}{cos^2 x} sin x)}{(5x + sec^2x)^2}$

$D_x y = frac{cos x (5x + sec^2 x) - sin x (5 + 2 sec x D_x frac{1}{cos x})}{(5x + sec^2x)^2}$

Differentiate sinx/(5x+sec^2x)sinx5x+sec2xsinx/(5x+sec^2x)?