Question

How do you differentiate # g(x) =cscx -x secx #?

Answer 1

`g'(x)=-cscxcotx-xsecxtanx-secx`

Explanation:

`g'(x)=-cscxcotx-[xsecxtanx+secx]->`product rule
`g'(x)=-cscxcotx-xsecxtanx-secx`