Question

How do you find the derivative of `2secx-cscx`?

Answer 1

`2sec(x)tan(x)+csc(x)*cot(x)`

Explanation:

Writing your function as
`f(x)=2(cos(x))^(-1)-(sin(x))^(-1)`
so we get
`f'(x)=-2(cos(x))^(-2)(-sin(x))+(sin(x))^(-2)*cos(x)`
and this is

`f'(x)=2sec(x)tan(x)+csc(x)*cot(x)`