What is the derivative of # sec x ^5#? Calculus Differentiating Trigonometric Functions Derivatives of y=sec(x), y=cot(x), y= csc(x) 1 Answer maganbhai P. Mar 6, 2018 #5x^4secx^5tanx^5# Explanation: #y=sec(x^5)rArr(dy)/(dx)=sec(x^5)tan(x^5)*d/(dx)(x^5)=sec(x^5)tan(x^5)(5x^4)=5x^4secx^5tanx^5# Answer link Related questions What is Derivatives of #y=sec(x)# ? What is the Derivative of #y=sec(x^2)#? What is the Derivative of #y=x sec(kx)#? What is the Derivative of #y=sec ^ 2(x)#? What is the derivative of #y=4 sec ^2(x)#? What is the derivative of #y=ln(sec(x)+tan(x))#? What is the derivative of #y=sec^2(x)#? What is the derivative of #y=sec^2(x) + tan^2(x)#? What is the derivative of #y=sec^3(x)#? What is the derivative of #y=sec(x) tan(x)#? See all questions in Derivatives of y=sec(x), y=cot(x), y= csc(x) Impact of this question 3900 views around the world You can reuse this answer Creative Commons License