What is the derivative of #Sec^2 pi(x) #?

Question

9148 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-07T15:05:30

#dy/dx = 2pisec^2pixtanpix#

Use the chain rule to differentiate #y=sec^2pix#

Let #u=secpix# and #y=u^2#

#dy/(du) = 2u=2secpix#

#(du)/dx= pisecpixtanpix#

Chain rule:

#dy/dx=dy/(du) xx (du)/dx#

#dy/dx = 2secpix xx pisecpixtanpix = 2pisec^2pixtanpix#