How can you derive the quotient rule?

1 Answer
Aug 19, 2014

This can be proven fairly quickly, assuming knowledge of prior subjects such as the product rule and chain rule. Suppose f(x) = (u(x))/(v(x))f(x)=u(x)v(x). As we know that all of our equations are in terms of xx, henceforth xx will be omitted from the steps below. Note however that it is still present as the variable for the functions.

(d/dx)f = (d/dx)u/v(ddx)f=(ddx)uv

Then via our definition f= u/vf=uv we get u= f*vu=fv. Differentiating this via use of the product rule nets us...

u' = f'*v + f*v'

Now as we isolate f' on its own side...

f'= [u'-f*v']/(v)

Recalling that f=u/v this becomes...

f' = [u' - (u/v)*v']/v

And by multiplying both the numerator and denominator by v we get...

f' = [u'*v - u*v']/[v^2]

Or, by showing x again...

f'(x) = [u'(x)*v(x) - u(x)*v'(x)]/(v(x))^2