How do I convert polar coordinates $(6, 60^{\circ})$ $(6, 60^circ)$ to rectangular coordinates?

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Answer 1 · 2014-09-11T06:08:28

$r a d i u s = r = 6$ $radius = r = 6$

$θ = 60$ $theta = 60$ degrees

Make appropriate substitutions for $r$ $r$ and $θ$ $theta$

$x = r cos (θ) \to 6 cos (60) = 6 \cdot \frac{1}{2} = 3$ $x= r cos (theta) -> 6cos(60) = 6 * 1/2 =3$

$y = r sin (θ) \to 6 sin (60) = 6 \cdot \frac{\sqrt{3}}{2} = 3 \sqrt{3}$ $y= r sin(theta) -> 6sin(60)=6*sqrt3/2=3sqrt3$

Solution: $(3, 3 \sqrt{3})$ $(3,3sqrt3)$

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How do I convert polar coordinates (6,60∘)(6, 60^circ) to rectangular coordinates?