How do you integrate $\frac{x + 1}{x^{2} + 2 x + 1}$ $(x+1)/(x^2+2x+1)$ ?

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Answer 1 · 2015-02-25T19:45:32

The answer is: $ln | x + 1 | + c$ $ln|x+1|+c$ .

this is because our function could be simplified:

$y = \frac{x + 1}{{(x + 1)}^{2}} \Rightarrow y = \frac{1}{x + 1}$ $y=(x+1)/(x+1)^2rArry=1/(x+1)$ ,

than:

$\int \frac{1}{x + 1} d x = ln | x + 1 | + c$ $int1/(x+1)dx=ln|x+1|+c$ .

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