How do you write an equation of a line with (4,0) and slope 1/3?

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How do you write an equation of a line with (4,0) and slope 1/3?

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Answer 1 · 2015-04-07T21:26:02

There are several ways to write an equation of the line with (4,0) and slope $\frac{1}{3}$ $1/3$ .

Use Point-Slope form
Use Slope-Intercept form

First, Point-Slope form : $y - y_{1} = m (x - x_{1})$ $y - y_1=m(x-x_1)$ where m is your slope, and the ordered pair you are given is $(x_{1}, y_{1})$ $(x_1,y_1)$ .
So write: $y - 0 = \frac{1}{3} (x - 4)$ $y - 0 = 1/3(x-4)$ .
Simplify if you wish: $y = \frac{1}{3} x - \frac{4}{3}$ $y = 1/3x-4/3$ .

Or, Slope-Intercept form : y = mx + b, where m is your slope, and b is the y-intercept (not given).
So, write: $y = \frac{1}{3} x + b$ $y = 1/3x+b$
Then, use your ordered pair to substitute in for x and y, and solve for b: $0 = (\frac{1}{3}) (4) + b$ $0 = (1/3)(4)+b$
$0 = \frac{4}{3} + b$ $0 = 4/3+b$ (subtract $\frac{4}{3}$ $4/3$ from both sides)
$\frac{- 4}{3} = b$ $(-4)/3=b$ and replace into the original form: $y = \frac{1}{3} x - \frac{4}{3}$ $y = 1/3x-4/3$

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How do you write an equation of a line with (4,0) and slope 1/3?

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