What is the range of the function #y = 2 sin x#? Precalculus Functions Defined and Notation Range 1 Answer Antoine Apr 22, 2015 The range of #sinx# is #-1<sinx<1# or #-1<y<1# It implies, #-2<2sinx<2# This means that the range of #y=2sinx# is #-2<y<2# Answer link Related questions What is the range of a function? What are some examples of range? How does the range of a function relate to its graph? What are common mistakes students make when working with range? How does the range of a function relate to its y-values? What is the range of a linear function? What is the range of a quadratic function? What is the range of a function like #f(x)=5x^2#? What is the range of a function like #f(x) = sqrt (x-5)#? How do I find the range of the function #f(x)=10-x^2#? See all questions in Range Impact of this question 5146 views around the world You can reuse this answer Creative Commons License