How do you solve: #sqrt(2x+5) - sqrt(x-2) = 3#?
1 Answer
Apr 25, 2015
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First isolate one of the square roots:
#sqrt(2x+5)=3+sqrt(x-2)# -
Then square each side:
#(sqrt(2x+5))^2=(3+sqrt(x-2))(3+sqrt(x-2))#
#2x+5=9+6sqrt(x-2)+(x-2)# -
Simplify the equations leaving the square root on one sided:
#x-2=6sqrt(x-2)# -
Square each side:
#(x-2)(x-2)=36(x-2)# -
Divide each side by (x-2):
#x-2=36#
so#x=38#
All ways check you answer in the original problem: