How do you solve $(2-x)log4=(5-x)log2$ ?

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Answer 1 · 2015-04-28T23:08:20

The answer is $x=-1$

log(4)= $log(2^2)$ = $2log(2)$

So, you can simplify $log(2)$
You have the linear equation $4-2x=5-x => x=-1$

How do you solve (2-x)log4=(5-x)log2(2-x)log4=(5-x)log2?