Question

How do you write the equation of a line in point slope form that is parallel to `y=-7x+1` and goes through (-1/2, -1/3)?

Answer 1

Line (1): y1 = -7x + 1.
Line y2, parallel to y1 must have slope same slope: -7.

`y2 = -7x + b.` Find b.

y2 passing at point `(-1/2, -1/3)` gives the equation:

`-1/3 = -7(-1/2) + b -> b = -1/3 - 7/2 = -23/6`

Answer: `y = -7x - 23/6`