How do you write the quadratic in vertex form given #x^2-7x + 9#? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Nghi N. · George C. May 15, 2015 #(-b/(2a)) = 7/2# #f(-b/(2a)) = 49/4 - 49/2 + 9 = -49/4 + 9 = -13/4# Factored form: #f(x) = (x - 7/2)^2 - 13/4# Check. Develop #f(x) = x^2 - 7x + 49/4 - 13/4 =x^2 - 7x + 9#. Correct Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 1825 views around the world You can reuse this answer Creative Commons License