How do you solve $5 \sqrt{x - 2} = 7$ $5 sqrt(x-2) =7$ ?

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Answer 1 · 2015-05-15T17:57:10

$\sqrt{x - 2} = \frac{7}{5}$ $sqrt (x - 2) = 7/5$

Square both sides:

$x - 2 = \frac{49}{25} \to x = \frac{49}{25} + 2 = \frac{99}{25}$ $x - 2 = 49/25 -> x = 49/25 + 2 = 99/25$

Answer 2 · 2015-05-15T17:57:23

$5 \sqrt{x - 2} = 7$ $5sqrt(x-2) = 7$

Divide both sides by $5$ $5$

$\sqrt{x - 2} = \frac{7}{5}$ $sqrt(x-2) = 7/5$

Square both sides

$x - 2 = {(\frac{7}{5})}^{2} = \frac{49}{25}$ $x-2 = (7/5)^2 = 49/25$

Add $2$ $2$ to both sides

$x = 2 + \frac{49}{25} = 3 \frac{24}{25}$ $x = 2 +49/25 = 3 24/25$

or to look like Katie's answer for those who prefer decimal fractions

$x = 3.96$ $x = 3.96$

How do you solve 5√x−2=7 5 sqrt(x-2) =7?