How do you write #y =-2x^2 + 12x - 13# in vertex form and identify the vertex? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Massimiliano May 24, 2015 The vertex form is: #y-y_v=a(x-x_v)^2#. So: #y=-2(x^2-6x)-13rArr# #y=-2(x^2-6x+9-9)-13rArr# #y=-2(x^2-6x+9)+18-13rArry=-2(x-3)^2+5rArr# #y-5=-2(x-3)^2#, and the vertex is #V(3,5)#. Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 5167 views around the world You can reuse this answer Creative Commons License