How do you simplify $\frac{36 m n^{3}}{24 m^{2} n^{5}}$ $(36mn^3)/(24m^2n^5)$ ?

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Answer 1 · 2015-05-27T19:48:04

Answer: $\frac{3}{2 m n^{2}}$ $3/(2mn^2)$

Working:

First, simplify $\frac{36}{24}$ $36/24$ :

Divide both the numerator and the denominator by 12 :
$= \frac{3}{2}$ $=3/2$

Rule : We know that $m^{x} \div m^{y} = m^{x - y}$ $m^(x)-:m^(y)=m^(x-y)$

So;

$\frac{3}{2} m^{(1 - 2)} n^{(3 - 5)} = \frac{3}{2} m^{- 1} n^{- 2}$ $3/2m^[(1-2)]n^[(3-5)]=3/2m^(-1)n^(-2)$

= $\frac{3}{2 m n^{2}}$ $3/(2mn^2)$

How do you simplify 36mn324m2n5(36mn^3)/(24m^2n^5)?