How do you solve by completing the square for 3x^2-12x+13x2−12x+1?

2 Answers
Elvan Burcu K.
May 29, 2015

3x^2 -12x +1 3x2−12x+1 if you add 8 than it will be like;
3x^2-12 +9 = (3x-3)*(x-3) 3x2−12+9=(3x−3)⋅(x−3) this is as far as i get.
But i think that some info is missing with that question. To completely solve this question;
3x^2 -12x +1 = A =>3x2−12x+1=A⇒ we should know this "A" value.
Since you didn't write that A value i cannot entirely solve the question . I 'm sorry :)

Alan P.
May 29, 2015

I will assume that what you really want to solve (by completing the square) is 3x^2-12x+1 = 03x2−12x+1=0

3x^2-12x+1 = 03x2−12x+1=0

x^2-4x = -1/3x2−4x=−13

x^2-4x+4 = 4-1/3x2−4x+4=4−13

(x-2)^2 = 11/3(x−2)2=113

x-2 = +-sqrt(11)/sqrt(3)x−2=±√11√3

x=2+sqrt(11)/sqrt(3)x=2+√11√3 or x=2-sqrt(11)/sqrt(3)x=2−√11√3

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