Question

How do you find the point-slope form of the equation of the line passing through the point (-1, -3) and has slope 5?

Answer 1

The main formula of a line is;
`y=ax+b`

We should use one point to find the real equation. If we use (-1,-3) point;
`y= ax+b => -3=-a+b`;
a is the slope of the equation, we found that as `5`;
`-3=(5*-1) + b => -3=-5 +b => b=2`;
So the equation of the line will be;
`y=ax+b => ul (y= 5x+2)`