What is the integral of #dy/e^y#? Calculus Introduction to Integration Integrals of Exponential Functions 1 Answer Equivirial Jun 6, 2015 #int dy/e^y=int e^{-y} dy= -e^{-y}+C# where #C# is the constant of integration. Answer link Related questions How do you evaluate the integral #inte^(4x) dx#? How do you evaluate the integral #inte^(-x) dx#? How do you evaluate the integral #int3^(x) dx#? How do you evaluate the integral #int3e^(x)-5e^(2x) dx#? How do you evaluate the integral #int10^(-x) dx#? What is the integral of #e^(x^3)#? What is the integral of #e^(0.5x)#? What is the integral of #e^(2x)#? What is the integral of #e^(7x)#? What is the integral of #2e^(2x)#? See all questions in Integrals of Exponential Functions Impact of this question 55220 views around the world You can reuse this answer Creative Commons License