Let $u(x)=e^(9x)$ and $v(x)=5x+9$ , how do you find $(v(u(x)))^2$ ?

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Answer 1 · 2015-06-07T01:26:36

Be $y = u(x) = e^(9x)$

$rarr v(u(x)) = v(y) = 5y+9 = 5e^(9x)+9$

$rarr (v(u(x)))^2 = (v(y))^2 = (5y+9)^2$

$= (5y+9)(5y+9) = (5*5*y*y)+(5*y*9)+(9*5*y)+(9*9)$

$= 25y^2+90y+81$

$= 25(e^(9x))^2+90e^(9x)+81$

$= 25e^(2*9x)+90e^(9x)+81$

$= 25e^(18x)+90e^(9x)+81$

Let u(x)=e^(9x)u(x)=e^(9x) and v(x)=5x+9v(x)=5x+9, how do you find (v(u(x)))^2(v(u(x)))^2?